An object is thrown upwards with speed of 50m/s.its height from the ground after 7 sec is
Answer»
Given, SPEED of object thrown above , u = 50m/s Time , t = 7sec Let object reach h hight in 7 sec from the ground ,when we thrown it with speed 50m/s .
Use formula, S = UT + 1/2at² here , s = h , a = -g and t = 7sec Now, h = 50 × 7 - 1/2 × 10 × (7)² = 350m - 245M = 105M