1.

An object is thrown with initial speed 5ms^(-1) with an angle of projection 30^(@). What is the maximum height and range reached by the particle?

Answer»


SOLUTION :MAX height reached `(H_(max))=(U^(2)sin^(2)theta)/(2g)=(25xx((1)/(2))^(2))/(2xx9.8)=0.318m`
Range `(R)=(u^(2)sin2theta)/(g)=(25xxsin60^(@))/(9.8)=2.21m`


Discussion

No Comment Found