An object is to be seen through a simple microscope of power 10 D. Where should the object be placed to reduce maximum angular magnification? The least distance for distinct vision is 25 cm.(a) + 7.1 cm(b) – 7.1 cm(c) + 25 cm(d) – 25 cmI have been asked this question in a job interview.The doubt is from Optical Instruments topic in portion Ray Optics and Optical Instruments of Physics – Class 12

An object is to be seen through a simple microscope of power 10 D. Whe

1.	An object is to be seen through a simple microscope of power 10 D. Where should the object be placed to reduce maximum angular magnification? The least distance for distinct vision is 25 cm.(a) + 7.1 cm(b) – 7.1 cm(c) + 25 cm(d) – 25 cmI have been asked this question in a job interview.The doubt is from Optical Instruments topic in portion Ray Optics and Optical Instruments of Physics – Class 12
Answer» Correct CHOICE is (b) – 7.1 cm Explanation: Angular magnification is maximum when the FINAL image is formed at the near point. \(\FRAC {1}{u} = \frac {1}{V} – \frac {1}{f}\) \(\frac {1}{u} = ( \frac {-1}{25} ) – ( \frac {1}{10} ) \) u = -7.1 cm. Therefore, the OBJECT should be placed 7.1 cm before the lens to avoid angular magnification.

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