InterviewSolution
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InterviewSolution
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An object moves from position (3,4) to (6,5) in the xy-plane. Find the magnitude and direction of displacement vector of the particle. |
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Answer» Positions of the particle are `r_(1) = x_(1) hati +y_(1) hatj = 3 hati +4hatj` and `r_(2) = x_(2) hati + y_(2) hatj = 6 hati + 5hatj` `:.` Displacement vector, `Deltar = (x_(2) - x_(1)) hati +(y_(2)-y_(1)) hati` `= (6-3) hati + (5-4) hatj = 3 hati +hatj` `:.` Magnitude of displacement vector, `|Deltar| = sqrt((3)^(2)+(1)^(2)) = sqrt(10)` Direction of `Deltar` with x axis, `theta = tan^(-1) ((Deltay)/(Deltax)) = tan^(-1) ((1)/(3)) ~~ 18.43^(@)` |
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