An object of 18 gram mass is lying on slope of 60^(@). If 36 dyne force act on it what will be its acceleration in horizontal direction ?

An object of 18 gram mass is lying on slope of 60^(@). If 36 dyne forc

1.	An object of 18 gram mass is lying on slope of 60^(@). If 36 dyne force act on it what will be its acceleration in horizontal direction ?
Answer» Solution :Horizontalcomponentof FORCE(in x-direction) `F_(x )= ` f cos `60^(@)` =18 DYNE Now`a_(x ) = (F_(x ))/( m )` `=(18)/(18)` `a_(x )= 1 CM^(2)` `mu= tantheta` `theta = tan^(-1)(mu)`