An object of height 10 cm is placed at a distance of 20 cm in front of a mirror. Its image is found at the same distance when it is placed. A. What is the type of the mirror? B. Is the image real or virtual? C. What is the height of the image?

An object of height 10 cm is placed at a distance of 20 cm in front of

1.	An object of height 10 cm is placed at a distance of 20 cm in front of a mirror. Its image is found at the same distance when it is placed. A. What is the type of the mirror? B. Is the image real or virtual? C. What is the height of the image?
Answer» ANSWERGiven that,Focal LENGTH f= 2R Radius of curvature R=30Object distance u=10cmHeight of object h o =2cmFrom the mirror FORMULA, f1 = V1 + u1 − v1 = u1 − f1 − v1 = 101 − 302 − v1 = 303−2 v=−30cmNow, the magnification is m= u−v m= 1030 m=3 Now, the height of image m= h o h i 3= 2H i h i =6CM Hence, the image distance is −30 cm, height of image is 6 cm and magnification is 3