An object of mass `10 kg` is launched from the ground at `t = 0`, at an angle of `37^(@)` above the horizontal with a speed of `30 m//s`. At some time after its launch, an explosion splits the projectile into two pieces. One piece of mass `4 kg` is observed at (`105 m, 43 m`) at `t =2 s`. Find the location of second piece at `t = 2 s`? A. `(10,2)`B. `(48,16)`C. `(10,-2)`D. information insufficient

An object of mass `10 kg` is launched from the ground at `t = 0`, at a

1.	An object of mass `10 kg` is launched from the ground at `t = 0`, at an angle of `37^(@)` above the horizontal with a speed of `30 m//s`. At some time after its launch, an explosion splits the projectile into two pieces. One piece of mass `4 kg` is observed at (`105 m, 43 m`) at `t =2 s`. Find the location of second piece at `t = 2 s`? A. `(10,2)`B. `(48,16)`C. `(10,-2)`D. information insufficient
Answer» Correct Answer - D As only the gravity force is acting on the system, the centre of mass of the system follows a parabolic path. At `t=2s`, `x_(CM)=30cos37^(@)xx2=48m` `y_(CM)=30sin37^(@)xx2-1/2xx10xx2^(2)=16m` Let coordinates of the second piece, i.. `6kg` piece be `(x,y)` Then `x_(CM)=48=(6x+4xx105)10impliesx=10m` `y_(CM)=16=(6y+4xx43)/10impliesy=-2m` Negative value of `y` shows that the second piece collides the ground before `t=2s`.

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