An object of mass 10 kg is moving with initial velocity of 2 ms-1 . To

1.	An object of mass 10 kg is moving with initial velocity of 2 ms-1 . To make it come to rest in one second, what should be the unbalanced force?
Answer» initial velocity = 2 ms^-1 velocity at rest = 0 ms^-1 time interval = 1 second mass m = 10 kg change in velocity in one second or acceleration \(=\frac{0-2}{1} \) = 2 ms^-1 F = ma F = 10 × 2 = 20 kg ms^-2 or -20 newton or-20 N. The negative sign tells us that the force exerted is opposite to the direction of motion.

An object of mass 10 kg is moving with initial velocity of 2 ms-1 . To make it come to rest in one second, what should be the unbalanced force?

Answer»

initial velocity = 2 ms^-1

velocity at rest = 0 ms^-1

time interval = 1 second

mass m = 10 kg

change in velocity in one second or acceleration

\(=\frac{0-2}{1} \) = 2 ms^-1

F = ma

F = 10 × 2

= 20 kg ms^-2 or -20 newton or-20 N.

The negative sign tells us that the force exerted is opposite to the direction of motion.