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An object of mass 3 kg is at rest . Now a force F=6t^(2)hati+2thatj is applied on the object . Find the velocity of the object at t=3 sec. |
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Answer» SOLUTION :Impulse `=int_(0)^(3) Fdt =int_(0)^(3) (6t^(2)hati+2thatj) dt =[2t^(3)hati+t^(2)hatj]_(0)^(3) =54hati+9hatj` Impulse= change in LINEAR MOMENTUM `54hati+9hatj=(vecv-vecu), 54hati+9hatj=3(vecv-vec0), vecv=(18hati+3hatj)m//s` |
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