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An object of mass 3 kg is at rest. Now a force of vecF=6t^(2)hati+4thatj is applied on the object, then the velocity of object at t=3 second is |
Answer» <html><body><p>`18hati+3hatj`<br/>`18hati+6hatj`<br/>`3hati+18hatj`<br/>`18hati+4hatj`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`F=<a href="https://interviewquestions.tuteehub.com/tag/6t-332119" style="font-weight:bold;" target="_blank" title="Click to know more about 6T">6T</a>^(2)hati+4thatj` <br/> `F=ma"":.a=(<a href="https://interviewquestions.tuteehub.com/tag/barf-2460769" style="font-weight:bold;" target="_blank" title="Click to know more about BARF">BARF</a>)/(m)=(1)/(3)(6t^(2)hati+4thatj)=<a href="https://interviewquestions.tuteehub.com/tag/2t-301164" style="font-weight:bold;" target="_blank" title="Click to know more about 2T">2T</a>^(2)hati+(4)/(3)thatj` <br/> `a=(dV)/(dt)"":.v=int_(0)^(t)adt=int_(0)^(3)2t^(2)hatjdt+int_(0)^(3)(4)/(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>)thatjdt=18hati+6hatj`</body></html> | |