An object of mass m and velocity v has kinetic energy = 200 J. Find th

1.	An object of mass m and velocity v has kinetic energy = 200 J. Find the new kinetic energy if the mass of the object becomes double and velocity still remains the same.
Answer» $\blue{\bold{\underline{\underline{Answer:}}}}$ $\green{\tt{\therefore{New\:kinetic\:energy=400\:J}}}$ $\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$ $\green{\underline \bold{<klux>GIVEN</klux> :}} \\ \tt: \implies Mass \: of \: object = m \\ \\ \tt: \implies Kinetic \: energy(K.E) = 200 \: joule\\\\ \tt:\implies Velocity\:of\:object\:=v \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies New \: kinetic\: energy= ?$ • ACCORDING to given QUESTION : $\bold{As \: we \: know \: that} \\ \tt: \implies Kinetic \: energy = \frac{1}{2} m {v}^{2} \\ \\ \tt: \implies 200 = \frac{1}{2} \times m \times {v}^{2} \\\\ \tt:\implies 400=mv^{2}-----(1)$ $\tt \circ \: mass = 2 m \\ \\ \bold{For \: new \: kinetic \: energy} \\ \tt: \implies K.E = \frac{1}{2} \times 2m \times {v}^{2} \\ \\ \tt: \implies K.E= m {v}^{2} - - - - - (2) \\ \\ \text{Putting \: value \: of \: mv}^{2} \text{ \: in \: (2)} \\ \\ \green{ \tt: \implies K.E = 400 \:J} \\ \\ \green{\tt \therefore New \: kinetic \:energy \: is \: 400 \: J}$

An object of mass m and velocity v has kinetic energy = 200 J. Find the new kinetic energy if the mass of the object becomes double and velocity still remains the same.

Answer»

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{New\:kinetic\:energy=400\:J}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{<klux>GIVEN</klux> :}} \\ \tt: \implies Mass \: of \: object = m \\ \\ \tt: \implies Kinetic \: energy(K.E) = 200 \: joule\\\\ \tt:\implies Velocity\:of\:object\:=v \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies New \: kinetic\: energy= ?$

• ACCORDING to given QUESTION :

$\bold{As \: we \: know \: that} \\ \tt: \implies Kinetic \: energy = \frac{1}{2} m {v}^{2} \\ \\ \tt: \implies 200 = \frac{1}{2} \times m \times {v}^{2} \\\\ \tt:\implies 400=mv^{2}-----(1)$

$\tt \circ \: mass = 2 m \\ \\ \bold{For \: new \: kinetic \: energy} \\ \tt: \implies K.E = \frac{1}{2} \times 2m \times {v}^{2} \\ \\ \tt: \implies K.E= m {v}^{2} - - - - - (2) \\ \\ \text{Putting \: value \: of \: mv}^{2} \text{ \: in \: (2)} \\ \\ \green{ \tt: \implies K.E = 400 \:J} \\ \\ \green{\tt \therefore New \: kinetic \:energy \: is \: 400 \: J}$

An object of mass m and velocity v has kinetic energy = 200 J. Find the new kinetic energy if the mass of the object becomes double and velocity still remains the same.

• ACCORDING to given QUESTION :

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