An object starting from rest and performing | 41 uniform accelerated motion gains 144 km/h speed in 20 s, then what will be distance covered in 20 s?

An object starting from rest and performing | 41 uniform accelerated m

1.	An object starting from rest and performing \| 41 uniform accelerated motion gains 144 km/h speed in 20 s, then what will be distance covered in 20 s?
Answer» 20 400 1440 2880 Solution :`U = 144 kmh^(-1) = (144000)/(3600) = 40ms ^(-1)` Now `d = ((V + v _(0))/( 2)) t = ((40 + 0)/(2)) 20` `therefore d = 400 m`