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An object weight 72 N the Earth. What its weight at a height R/2 from Earth. |
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Answer» Solution :We KNOW that`G = GM` ` g. = g (R/(R+h))^(2) = g(R/(R+R/2))^(2) = g ((2R)/(3R))^(2)` `g . = 4/9 g ` WEIGHT W. = `4/9 W = 4/9 (72)` |
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