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An observer A is at rest in gournd frame, observer B is moving with constant another observer C is moving with constant velocity of 1m/s. A. work done by all forces (both real and pseudo) in 1 sec in frame of A is 0.5JB. work done by all forces (both real and pseudo) in 1 sec in frame of B is 0JC. work done by all force (both real and pseudo) in 1 sec in frame of C is -0.5JD. change in K.E. in frame of B is zero |
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Answer» `S=(1)/(2)at^(2)=(1)/(2)xx1xx1^(2)=(1)/(2)m` `omega_(A)=1xx(1)/(2)=0.5J` `omega_(B)=0` because in frame 1 ke is at rest. `omega_(C)=DeltaK=0-(1)/(2)=-(1)/(2)J` `k_(i)=(1)/(2)xx1xx1^(2)` `k_(r)=0` |
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