An observer is moving with half the speed of light towards a stationary microwave source emitting waves at frequency 10 GHz. What is the frequency of the microwave measured by the observer? (speed of light = 3 xx 10^(8)m cdot s^(-1))

An observer is moving with half the speed of light towards a stationar

1.	An observer is moving with half the speed of light towards a stationary microwave source emitting waves at frequency 10 GHz. What is the frequency of the microwave measured by the observer? (speed of light = 3 xx 10^(8)m cdot s^(-1))
Answer» `10.1` GHz `12, 1 ` GHz `17.3` GHz `15.3` GHz Solution :Speed of the observer `=c/2` `therefore ` Doppler effect in relevant with the theory of relativity as follows: `V.=vsqrt((1+beta)/(1-beta))` `beta = (" speed of observer " ) / (" speed of light " ) = 1/2` `therefore v. = 10 SQRT((1+1/2)/(1-1/2))=10sqrt(3) = 10 xx 1.73` `=17.3` GHz The OPTION (c) is CORRECT.