An observer is moving with half the speed of light towards a stationary microwave source emitting waves at frequency 10GHz. What is the frequency of the microwave measured by the observer ? ( speed of light =3xx10^(8)ms^(-1))

An observer is moving with half the speed of light towards a stationar

1.	An observer is moving with half the speed of light towards a stationary microwave source emitting waves at frequency 10GHz. What is the frequency of the microwave measured by the observer ? ( speed of light =3xx10^(8)ms^(-1))
Answer» `17.3GHz` `15.3GHz` `10.1GHz` `12.1GHz` Solution :Here, `V=10GHz, v^(')=?` `upsilon=(C)/(2)` and `c=3xx10^(8)m//s` As speed of OBSERVER is not very much less than the speed of light , therefore, `v^(')=sqrt((1+upsilon//c)/(1-upsilon//c))xxv=sqrt((1+1//2)/(1-1//2))xxv` `=sqrt(3)xx10GHz=17.3GHz`