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An observer moves towards a stationary source of sound, with a velocity one-fifth of the velocity of sound. What is the percentage increase in the apparent frequency?A. `5%`B. `20%`C. `0%`D. `0.5%` |
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Answer» Correct Answer - B `f=f_0((v_S+v_0)/(v_S))` `=f_0[(v+(v)/(5))/(v)]` `=(6)/(5)f_0` Hence, percentage increase is `[((6)/(5)f_0-f_0)/(f_0)]xx100=20%` |
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