An oil drop falls through air with a terminal velocity of 5×10−4 m/s. The radius of the drop will be:Neglect density of air compared to that of oil. (Viscosity of air =18×10−55 N.s/m2,g=10 m/s2, density of oil =900 kg/m3

An oil drop falls through air with a terminal velocity of 5×10−4 m/

1.	An oil drop falls through air with a terminal velocity of 5×10−4 m/s. The radius of the drop will be:Neglect density of air compared to that of oil. (Viscosity of air =18×10−55 N.s/m2,g=10 m/s2, density of oil =900 kg/m3
Answer» An oil drop falls through air with a terminal velocity of $5 \times 10^{- 4} m/s$ . The radius of the drop will be: Neglect density of air compared to that of oil. (Viscosity of air $= \frac{18 \times 10^{- 5}}{5} {N.s/m}^{2}, g = 10 {m/s}^{2}$ , density of oil $= 900 {kg/m}^{3}$

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An oil drop falls through air with a terminal velocity of 5×10−4 m/s. The radius of the drop will be:Neglect density of air compared to that of oil. (Viscosity of air =18×10−55 N.s/m2,g=10 m/s2, density of oil =900 kg/m3

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