1.

An oleum sample is labelled as 113.5`%`. Identity the incorrect statementA. The amount of free `SO_(2)` in 50g oleum sample is 30 gB. The amount of `H_(2)SO_(4)` in 50g oleum sample is 30gC. The new labelling of oleum sample when 8 g water is added in 100 g original oleum sample is `(100+(137.5)/(27))%`D. In the original 50g oleum sample when 6.75 g is added then 56.75g `H_(2)SO_(4)` is produced.

Answer» Correct Answer - B


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