Saved Bookmarks
| 1. |
An open pipe resonates with frequency 100Hz and a closed pipe resonates with frequency 50Hz. If they are joined to form a longer tube then it will resonate with frequency of (neglect end corrections) |
|
Answer» `25Hz` `n_(1)=(V)/(2l_(0))`, `n_(2)=(V)/(4l_(c ))` `impliesl_(0)=(V)/(2n_(1))`, `L_(c )=(V)/(4n_(2))` `:.l_(0)+l_(c )=(V)/(4n)` `(V)/(2n_(1))+(V)/(4n_(2))=(V)/(4n)impliesn=(n_(1)n_(2))/(n_(1)+2n_(2))` |
|