1.

An open pipe resonates with frequency 100Hz and a closed pipe resonates with frequency 50Hz. If they are joined to form a longer tube then it will resonate with frequency of (neglect end corrections)

Answer»

`25Hz`
`50Hz`
`75Hz`
`100Hz`

SOLUTION :
`n_(1)=(V)/(2l_(0))`, `n_(2)=(V)/(4l_(c ))`
`impliesl_(0)=(V)/(2n_(1))`, `L_(c )=(V)/(4n_(2))`
`:.l_(0)+l_(c )=(V)/(4n)`
`(V)/(2n_(1))+(V)/(4n_(2))=(V)/(4n)impliesn=(n_(1)n_(2))/(n_(1)+2n_(2))`


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