1.

An open vessel at 27°C is heated until 3/5th of the air in it has been expelled. Assuming the volume of the vessel remainsconstant, find the temperature to which the vessel has been heated?(A) 477° C(B) 437°C(C) 450°C(D) 485°C

Answer»

Since the vessel is open to the air the number of molecules of air is not fixed, but the pressure and temperature are. As the vessel is heated air will escape from it so that the pressure remains constant.

n1T1 = n2T2 ................... from PV=nRTT2 = n1T1 / n1 ................ solve for T2T2 = 5/5 x 300K / 2/5T2 = 750K ............ or ............. 477C



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