InterviewSolution
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InterviewSolution
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An optically pure compound `A,` gave an `[alpha]_(D)^(25)=+30^(@),` while a mixture of `A` and its enantiomer `B`, gave `[alpha]_(D)^(25)=+15^(@),` . The ratio of `A` to `B` in the mixture isA. 1 to 3B. 3 to 1C. 1 to 2D. 2 to 1 |
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Answer» Correct Answer - B `(15)/(30)xx100=50` Thus the mixture is 50% opticaaly pure. Hence the amount of `A=50+25=75 B=0+25=25` |
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