An optically pure compound X gave an [alpha]_(D)^(25)=+20.0^(@) A mixture of X and its enantiomer Y gave [alpha]_(D)^(25)=+10^(@). The ratio of X to Y in the mixture is :

An optically pure compound X gave an [alpha]_(D)^(25)=+20.0^(@) A mixt

1.	An optically pure compound X gave an [alpha]_(D)^(25)=+20.0^(@) A mixture of X and its enantiomer Y gave [alpha]_(D)^(25)=+10^(@). The ratio of X to Y in the mixture is :
Answer» `2:1` `1:3` `3:1` `1:2` SOLUTION :OPTICAL purity `=(100)/(20)xx100=50%`i.e.,AMOUNT of X Hence optical IMPURITY =100 - 50 = 50% TotalX= 50 +25 =75% TotalY= 25% Hence, ratio of X and Y = 75 : 25 3 : 1