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An orange precipitate of group II is dissolve in cone HCI the solution when treated with excess of water turn milky due to formation ofA. Sn(OH)CIB. `Sb(OH)CI_(2)`C. SbOCID. `Sb(OH)_(2)Cl` |
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Answer» Correct Answer - c `Sb_(2)S_(3) + 6HCI rarr 2SbCI_(3) + 3H_(3)S` `SbCI_(3) + H_(2)O rarr SbOCI + 2HCI` |
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