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An organic compound A of molecular formula C_2H_2 reacts with HCI to give C_2H_4Cl_2 as B.B on reaction with aqueous KOH will give C_2H_4O as C. Identify A, B,C,and explain the reaction involved. |
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Answer» Solution :(i) An organic compoundA of molecular FORMULA `C_2H_2 ` is ` CH -=CH` (Acetylene) (ii) Acetylene A reacts with HCI to give ethylene dichloride B as the PRODUCT. `underset("Acetylene")undersetA(CH-=CH)+ HCl to underset(CL) underset(|)CH_2 = CH overset(HCl)to underset(B)underset("dichloride ")underset("Ethylidene")(CH_3 - CHCl_2)` (III) Ethylidene dichloride on reaction with aqueous KOH will give acetaldehyde, C as the product.
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