An organic compound A of molecular formula CH_(2)O reacts with methyl magnesium iodide followed by acid hydrolysis to give B of molecular formula C_(2)H_(6)O. B on reaction with PCl_(5) gives C. C on reaction with alcoholic KOH gives D an alkene as the product. Identify A,B,C,D and explain the reactions involved.

An organic compound A of molecular formula CH_(2)O reacts with methyl

1.	An organic compound A of molecular formula CH_(2)O reacts with methyl magnesium iodide followed by acid hydrolysis to give B of molecular formula C_(2)H_(6)O. B on reaction with PCl_(5) gives C. C on reaction with alcoholic KOH gives D an alkene as the product. Identify A,B,C,D and explain the reactions involved.
Answer» Solution :1. A of molecular formula `CH_(2)O` is identified as `HCHO`, formaldehyde. 2. Formaldehyde reacs with `CH_(3)MgI` followed by hydrolysis to give ethanol, `CH_(3)-CH_(2)OH` B as the product. 3. Ethanol B reacts with `PCl_(5)` to give `C_(2)H_(5)Cl` Ethyl chloride C as the product. `underset("Ethanol")(CH_(3)-CH_(2)OH)+PCl_(5)overset(HOH)(to)CH_(3)-underset("Ethyl chloride C")(CH_(2)Cl+POCl_(3)+)HCL` 4. `CH_(3)-CH_(2)Cl` C on reaction with alcoholic KOH UNDERGOES dehydrohalogenation to give ethylene `CH_(2)=CH_(2)` D as the product. `CH_(3)-CH_(2)Clunderset("KOH")overset("alcoholic")(to)underset("Ethylene")(CH_(2)=CH_(2)+)HCl` `{:(A,HCHO,"Formaldehyde"),(B,CH_(3)-CH_(2)OH,"Ethanol"),(C,CH_(3)-CH_(2)Cl,"Ethyl chloride"),(D,CH_(2)-CH_(2),"Ethylene"):}`