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An organic compound (A) with molecularformula C_2H_5Cl reacts with KOH gives compounds (B) and with alcoholic KOH gives compound (C). Identify (A), (B) and (C)

Answer»

Solution :
(i) An organic compound (A) of molecular formula `C_2H_5Cl` is identified as Chloroethane with molecular formula `CH_3 - CH_2Cl` from the formula.
(ii) Chloroethane reacts with AQUEOUS KOH to GIVE ETHANOL, i.e., Aqueous `C_2H_5OH`as (B) by substitution reaction.
`CH_3 - CH_2Cl + KOH to UNDERSET("Ethanol (B)")(CH_3 - CH_2OH) + KCl`
(iii) Chloroethane reacts with alcoholic KOH to give ethene `C_2H_4` as (C) by elimination reaction.
`CH_3 - CH_2Cl underset(KOH)OVERSET("alcoholic")toCH_2=CH_2 + KCl + H_2O`


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