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An organic compound containing carbon hydrogen and oxygen contains 52 .2 % carbon and 13.04 % hydrogen .Vapour density of the compound is 23 .Its molecular formula will beA. `C_(2)H_(6)O`B. `C_(3)H_(6)O`C. `C_(4)H_(8)O`D. `C_(5)H_(10)O` |
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Answer» Correct Answer - A Precentage of O=100-(52.2+13.04)=34.76 Ratio of atoms C:H:O`=(52.2)/(12):(13.04)/(1):(34.76)/(16)` `=4.35:13:04:2.17=2:6:1.` E.F`=C_2H_6O` E.F mass `=2xx12+6xx1+1xx16=46` Mol.mass `=2xxV.D=2xx23=46` `n=("Mol.mass")/("E.F mass")=46/46=1` `therefore MF=(E.F.)_(n)=(C_2H_6O)_(1)=C_2H_6O` |
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