An organic compound contains `C = 40%, H = 13.33%`, and `N = 46.67%`. Its empirical formula will beA. `CHN`B. `C_(3)H_(7)N`C. `C_(2)H_(2)N`D. `CH_(4)N`

An organic compound contains `C = 40%, H = 13.33%`, and `N = 46.67%`.

1.	An organic compound contains `C = 40%, H = 13.33%`, and `N = 46.67%`. Its empirical formula will beA. `CHN`B. `C_(3)H_(7)N`C. `C_(2)H_(2)N`D. `CH_(4)N`
Answer» Correct Answer - D Considering `100 g` of the compound, we have `m_(C ) = 40 g, m_(H) = 13.33 g`, and `m_(N) = 46.67 g` Thus, the ratio of moles will be `n_(C ):n_(H):n_(N) = (40)/(12) : (13.33)/(1) : (46.67)/(14)` `= 3.33 : 13.33 : 3.33` `= (3.33)/(3.33) : (13.33)/(3.33) : (3.33)/(3.33)` `= 1 : 4 : 1` Thus, the empirical formula is `CH_(4)N`.

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An organic compound contains `C = 40%, H = 13.33%`, and `N = 46.67%`. Its empirical formula will beA. `CHN`B. `C_(3)H_(7)N`C. `C_(2)H_(2)N`D. `CH_(4)N`

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