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An organic compound contains carbon, hydrogen and oxygen. Its elemental analysis gave, C 38.71% and H, 9.67%.The empirical formula of the compound would beA) CH3OB) CH2OC) CHOD) CH40 |
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Answer» let the total mass of compound be 100 so, C = 38.71g => mol of C = 38/12 = 3 H = 9.67g => mol of C = 9.67/1 = 9 O = (100-38.7-9.6) = 52g => mol of O = 52/16 = 3 so, Chemical formula = C3H9O3 emperical formula = CH3O |
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