1.

An organic compound gave the following results on analysis, 0.2496 g of the compound gave 0.3168 g of `CO_(2)` and 0.0864 g of `H_(2)O`. Calculate the percentage of carbo and hydrogen in the compound.

Answer» Correct Answer - `C = 34.61 %, H= 3.84 %`
`%` of `C=12/44xx("Mass of "CO_(2))/("Mass of compound")xx100=12/44xx0.3168/0.2496xx100= 34.61%`
`%` of `H=2/18xx("Mass of "H_(2)O)/("Mass of compound")xx100=2/18xx0.0864/0.2496xx100= 3.84 %`


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