1.

An organic compound `%` of C and % of H in the ratio `6 : 1` and `%` of C and % of O in the ratio `3 : 4`. The compound isA. `HCHO`B. `CH_(3)OH`C. `CH_(3)CH_(2)OH`D. `(COOH)_(2)`

Answer» Correct Answer - A
Let `%` of hydrogen is x then `%` of carbon is `6x` and `%` of Oxygen is `8x`
i.e., `x+6x+8x=100 rArr x = (100)/(15)`
`C 600//15% rArr 40//12 = 3.3333 rArr 1`
`H 100//15% rArr 100//15 = 6.6667 rArr 2`
`O 800//15% rArr 50//15 = 3.333 rArr 1`
`CH_(2)O` is the empirical formula.


Discussion

No Comment Found

Related InterviewSolutions