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An organic compound `%` of C and % of H in the ratio `6 : 1` and `%` of C and % of O in the ratio `3 : 4`. The compound isA. `HCHO`B. `CH_(3)OH`C. `CH_(3)CH_(2)OH`D. `(COOH)_(2)` |
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Answer» Correct Answer - A Let `%` of hydrogen is x then `%` of carbon is `6x` and `%` of Oxygen is `8x` i.e., `x+6x+8x=100 rArr x = (100)/(15)` `C 600//15% rArr 40//12 = 3.3333 rArr 1` `H 100//15% rArr 100//15 = 6.6667 rArr 2` `O 800//15% rArr 50//15 = 3.333 rArr 1` `CH_(2)O` is the empirical formula. |
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