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An organic compound on analysis gave the following data: (i). 0.25 gm of the compound on complete combustion gave 0.37 gm of `CO_2` and 0.2 gm of water. (ii). 0.25 gm of the compound on analysis by Dumas method gave 32 ml of nitrogen gas at STP. Calculate the percentages of `C,H,N` and `O `in the organic compounds. |
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Answer» (i) Calculation of percentage of carbon. Mass of the compound =0.25 g Mass of carbon dioxide formed =0.37 g Percentage of carbon `=12/44xx("Mass of "CO_(2))/("Mass of compound")xx100=12/44xx0.37/0.25xx100=40.36` (ii) Calculation of percentage of hydrogen Mass of the compound =0.25 g Mass of water formed =0.20 g Percentage of hydrogen `=2/18xx("Mass of "H_(2)O)/("Mass of compound")xx100=2/18xx0.20/0.25xx100=8.89` (iii) Calculation of persentage of nitrogen. Mass of the compound = 0.25 g Volume of `N_(2)` evolved at N.T.P. = 32 mL Percentage of nitrogen `=28/22400xx("Volume of "N_(2)" at N.T.P.")/("Mass of compound")xx100=28/22400xx32.0/0.25xx100=16.0` |
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