An organic compound on analysis was found to contain 16.27% carbon. 0.67% Hydrogen, 72.2% chlorine. The V.D. of the compound is equal to 73.75. Calculate the empirical formula and molecular formula of the compound.

An organic compound on analysis was found to contain 16.27% carbon. 0.

1.	An organic compound on analysis was found to contain 16.27% carbon. 0.67% Hydrogen, 72.2% chlorine. The V.D. of the compound is equal to 73.75. Calculate the empirical formula and molecular formula of the compound.
Answer» Solution : EMPIRICAL FORMULA of the compound `=C_(2)HCl_(3)O` `(2xx 12)+(1 XX 1)+(3 xx 35.5) +(1 xx 16)=147.5` Molecular weight `=2x V.D. =2 xx 73.75=147.50` `n=("Molecular weight")/("Empirical formula weight")=(147.50)/(147.50)=1` Molecular formula `=C_(2)HCl_(3)O`