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An organic compound was found to contain the following percentage composition: H = 2.22%, C = 26.65%, O = 71.11%  Find its empirical formula [H = 1, C = 12, O = 16]

Answer»
ElementSymbolRel. At. mass% comp.Relative no. of atomSimple ratio Simple whole no. ratio
HydrogenH12.22 2.22/1=2.222.22/2.22=11
CarbonC1226.6726.67/12=2.222.22/2.22=1 1 1
OxygenO1671.1171.11/16=4.444.44/2.22=2 2

Empirical formula – H1C1O2 = HCO2



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