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An organic compound with C =40 % and H= 13.33 % and N=46.67 % Its empirical empirical formula would beA. CHNB. `C_(2)H_(2)N`C. `CH_(4)N`D. `C_(3)H_(7)N` |
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Answer» Correct Answer - C Ratio of C:H:N `=(40)/(12):(13.33)/(1)=(46.67)/(14)=1:4:1` Empirical formula `=CH_2O` |
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