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An organic compound with C =40 % and H= 6.7% will have the empirical formulaA. `CH_(4)`B. `CH_(4)O`C. `C_(3)H_(6)O_(3)`D. `C_(2)H_(4)O_(2)` |
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Answer» Correct Answer - B Ratio of C:H:O `=40/12:(6.7)/(1):(53.33)/(16)=1:2:1` Hence Empirical formula `=CH_O` |
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