An organic compound x having molecular mass 60 is found to contain C = 20%, H = 6.67% and N = 46.67%, while rest is oxygen. On heating, it gives ammonia along with a solid residue. The solid residue gave violet colour with alkaline copper sulphate solution. The compound X is

An organic compound x having molecular mass 60 is found to contain C =

1.	An organic compound x having molecular mass 60 is found to contain C = 20%, H = 6.67% and N = 46.67%, while rest is oxygen. On heating, it gives ammonia along with a solid residue. The solid residue gave violet colour with alkaline copper sulphate solution. The compound X is
Answer» `CH_(3)CH_(2)CONH_(2)` `CH_(3)NCO` `CH_(3)CONH_(2)` `(NH_(2))_(2)CO` Solution :`%O = 100 - (20.0 + 6.67 + 46.67) = 26.66` `C:H:N:O = (20)/(12) : (6.67)/(1.0) : (46.67)/(14) : (26.66)/(16)` = 1.67 : 6.67 : 3.33 : 1.67 = 1 : 4 : 2: 1 `:. E.F. = CH_(4)N_(2)O` Now E.F. wt. = 12 + 4 + 28 + 16 = 60 and Mol. Wt = 60 (given) `:. M.F. = E.F. xx ("Mol. wt.")/("E.F. wt") = CH_(4)N_(2)O xx (60)/(60)` `= CH_(4)NH_(2)O` Now out of the given FOUR compounds `(CH_(3)CH_(2)CONH_(2) (a) = C_(3)H_(7)NO, CH_(3)CONH_(2) (c) = C_(2)H_(5)NO, CH_(3)NCO (b) = C_(2)H_(3)NO)`, the `CH_(4)N_(2)O`, there-fore, the given compound is urea, `NH_(2)CONH_(2)`. Further since urea on heating loses `NH_(3)` and gives a residue called biuret which gives a violet colouration with alk. `CuSO_(4)` solution, therefore, the given organic compound is `NH_(2)CONH_(2)`, i.e., option (d) is correct. `underset("Biuret")(NH_(2)CONHCONH_(2)) OVERSET(Alk. CuSO_(4))rarr` Violet colouration