An organic compoundA of molecular formula C_2H_6O reacts with thionyl chloride in the presence of pyridine gives B C_2H_5Cl. B on reaction with alcoholic KOH gives C. C_2H_4, C on treatment with Cl_2 gives C_2H_4Cl_2 as D. Identify A,B,C,D and explain the reaction.

An organic compoundA of molecular formula C_2H_6O reacts with thionyl

1.	An organic compoundA of molecular formula C_2H_6O reacts with thionyl chloride in the presence of pyridine gives B C_2H_5Cl. B on reaction with alcoholic KOH gives C. C_2H_4, C on treatment with Cl_2 gives C_2H_4Cl_2 as D. Identify A,B,C,D and explain the reaction.
Answer» Solution :(i) An organic COMPOUND A of molecular formula `C_2H_6O` is Ethanol `CH_3- CH_2OH`. (ii) Ethanol reacts with thionyl chloride in the presence of pyridine to give `CH_3 - CH_2Cl` B as product. `CH_3-CH_2OH underset("Pyridine")overset(SoCl_2)to underset("Ethyl chloride"B)(CH_3 - CH_2Cl)` (iii) Ethyl chloride on treatment with alcoholie KOH, undergoes dehydrohalogenation to give `C_2H_4`, ethylene C as the product. `CH_3 - CH_2Cl underset(KOH)overset("alcoholic")to underset("Ethylene C")(CH_2= CH_2) + KCL + H_2O` (IV) Ethylene on reaction with `Cl_2` yield ethylenedichloride as D as the product.