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An organic compund (A) has a molecular formula C_(2)H_(6)O it is one of the primary alcohol. A reacts with acidified potassium dichromate to give B.B on further undergoes to oxidation reaction to give C.C on reacts with SOCI_(2) to give D which is chlorinated product.Identify A,B,C and D, explain the equation. |
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Answer» Solution :(i) `C_(2)H_(6)O` is `CH_(3)-CH_(2)-OH` which is a primary alcohol (A). (II) `CH_(3)-CH_(2) -OH (A)` reacts with `H^(+)/K_(2)Cr_(2)O_(7)` to give ACETALDEHYDE (B) `underset"(Ethanol (A)" (CH_(3)- CH_(2) - OH) overset (H^(+)//K_(2)Cr_(2)O_(7)) to underset ("Acetaldehyde (B)")(CH_(3)CHO )` (iii) `CH_(3)CHO(B)` which on further oxidation to give acetic ACID (C). `underset("Acetaldehyde (B)")(CH_(3)CHO) overset("O") to underset("Acetic Acid (C)")(CH_(3)COOH)` (iv) Acetic acid reacts with `SOCI(2)` to give ACETYL chloride (D). `underset("Acetic acid (C)") (CH_(3)COOH)overset("O") to underset ("Acetyl chloride (D)") (CH_(3)COCI+ SO_(2) + HCI)` `{: ( "(A)`CH_(3)-CH_(2)-OH`", "Ethanol"),( "(B)`CH_(3)CHO`", "Acetaldehyde") , ("(C)`CH_(3)COOH`" , "Acetic acid"),("(D)`CH_(3)COCI` " ,"Acetyl chloride") :}` |
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