An organic fruit smelling compound on analysis has the following composition by mass: C = 54.54%, H = 9.09%, O = 36.36%. Find out the molecular formula of the compound. The vapour density of the compound was found to be 44

An organic fruit smelling compound on analysis has the following compo

1.	An organic fruit smelling compound on analysis has the following composition by mass: C = 54.54%, H = 9.09%, O = 36.36%. Find out the molecular formula of the compound. The vapour density of the compound was found to be 44
Answer» SOLUTION : `:.` The empirical formula is `C_(2)H_(4)O`. The empirical formula mass `(C_(2)H_(4)O) = (12xx2) + (1xx4) + (16xx1)` = 44 Molecular mass = 2`XX` Vapour density = `2xx44=88` N = `("Molecular mass")/("Empirical formula mass")=88/44=2` Molecular formula = ` ("Empirical formula")_(n)` = `(C_(2)H_(4)O)_(2)` `:.`Molecular formula = `C_(4)H_(8)O_(2)`