An organic ompound contains C = 48, H = 8%. 0.48g of the compound was Kjeldahlised and the liberated ammonia required 19.2mL N//2 H_(2)SO_(4). Find the empirical formula of the compound.

An organic ompound contains C = 48, H = 8%. 0.48g of the compound was

1.	An organic ompound contains C = 48, H = 8%. 0.48g of the compound was Kjeldahlised and the liberated ammonia required 19.2mL N//2 H_(2)SO_(4). Find the empirical formula of the compound.
Answer» Solution :Percentage of nitrogen `= (1.4 xx N_(1) xx V_(1))/(W)` `W =` Mass of ORGANIC compound `= 0.48g` `N_(1) = (1)/(2) = 0.5, V_(1) = 19.2 mL` Percentage of `N = (1.4 xx 0.5 xx 19.2)/(0.48) = 28` Percentage of oxygen `= 100 - (48 +8 +28) = 16` Calculation of EMPIRICAL FORMULA. `{:("Element","Percentage","At.mass","Relative number of ATOMS","Simplest ratio of atoms"),("Carbon",48.0,12,(48)/(12)=4,(4)/(1)=4),("Hydrogen",8.0,1,(8)/(1)=8,(8)/(1)=8),("Nitrogen",28.0,14,(28)/(14)=2,(2)/(1)=2),("Oxygen",16.0,16,(16)/(16)=1,(1)/(1)=1):}` Empirical formula `= C_(4)H_(8)N_(2)O`