1.

An ornament weighting 36 gin air, weighs ony 34 g in water. Assuming that some copper is mixed wilth godl to prepare the ornament, find the amount of coper in it. Specific gravity of godl is 19.3 and that of copper is 8.9.

Answer»


SOLUTION :Given that `m_1a=36gm`
`m_2 water =34GM`
Density of GOLD `rho_(An)=19.3gm/cc`
` Density of copper, rho_(Cu)=8.9gm/cc`
we know that loss of `wt=wt` of displaced water
`=36-34=2gm
Here, `m_c=m_(Au)+m_(Cu)`
`=36gm`…….i
Let v be the volume of the orN/Ament in cm.
S, `Vxxrho_wxx=2xxg`
`rarr (v_(Au)+V_(Cu))xxrho_wxxg=2xxg`
`rarr (m/(rho_(Au))+m/(rho_(Cu)))rho_wxxg=2xxg`
`rarr ((m_(Au))/19.3+(m_(Cu))/8.9)x1=2`
`rarr 8.9m_(Au)+19.3m_(Cu)=2xx19.3x8.9`
`=343.54`..........ii
`Form eq i and ii ltbr. `8.9(m_(Au)+m_(Cu))=8.9xx36`
i. `8.9m_(Au)+8.9m_(Cu)=320.40`.........iii ltbr. `from ii and iii we get ,
`10.4m_(Cu)=23.14`
`=m_(Cu)=2.225gm`
so the AMOUNT of copper in the oerN/Ament is 2.2g.


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