An oxygen containing organic compound was found to contain 53% carbon and 13% hydrogen. Its vapour density is 23. The compound reacts with sodium metal to liberate hydrogen. Identify the functional isomer of this compound.

An oxygen containing organic compound was found to contain 53% carbon

1.	An oxygen containing organic compound was found to contain 53% carbon and 13% hydrogen. Its vapour density is 23. The compound reacts with sodium metal to liberate hydrogen. Identify the functional isomer of this compound.
Answer» Solution :% O = 100 - (53 + 13) = 34 `:.` Ratio of atoms, `C : H : O = (53)/(12) : (13)/(1) : (34)/(16) = 4.4 : 13 : 2.125 = 2 : 6 : 1` `:. E.F. = C_(2)H_(6)O` andE.F. wt `= 2 XX 12 + 6 xx 1 + 1 xx 16 = 46` Mol. wt. `= 2 xx V.D. = 2 xx 23 = 46` `:.` n = Mol. wt/E.F. wt. `= (46)/(46) = 1` Thus, M.F. `= 1 xx E.F. = C_(2)H_(6)O` Since the given organic compound reacts with sodium o liberate `H_(2)` gas, therefore, it must be ethanol. `underset("Ethanol")(2CH_(3)CH_(2)OH)+2Na rarr 2CH_(3)CH_(2)ONa+H_(2)` The functional ISOMER of ethanol is methoxymethane, i.e., `CH_(3)OCH_(3)`.