1.

An SHM is given by x=8sin(10pit+pi/4)m.At which position will its kinetic energy become equal to its potential energy.

Answer»

SOLUTION :When KE=`PE,1/2momega^2(A^2-y^2)=1/2momega^2y^2`
1/2`momega^2A^2-/2momega^2y^2=1/2momega^2y^2` then `y=A/sqrt2 thereforey=8/sqrt2`=5.66m


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