InterviewSolution
Saved Bookmarks
| 1. |
An solid cylinder of mass `20 kg` and radius `20 cm` rotates about its axis with a angular speed `100 rad s^-1`. The angular momentum of the cylinder about its axis is.A. 40 J sB. 400 J sC. 20 J sD. 200 J s |
|
Answer» Correct Answer - A (a) Here, `M = 20 kg` `R = 20 cm = 20 xx 10^-2 m, omega = 100 rad s^-1` Moment of inertia of the solid cylinder about its axis is. `I = (MR^2)/(2) = ((20 kg)(20 xx 10^-2 m)^2)/(2) = 0.4 kg m^2` Angular momentum of the cylinder about axis is. `L = I omega = (0.4 kg m^2)(100 rad s^-1) = 40 J s`. |
|