1.

An solid cylinder of mass `20 kg` and radius `20 cm` rotates about its axis with a angular speed `100 rad s^-1`. The angular momentum of the cylinder about its axis is.A. 40 J sB. 400 J sC. 20 J sD. 200 J s

Answer» Correct Answer - A
(a) Here, `M = 20 kg`
`R = 20 cm = 20 xx 10^-2 m, omega = 100 rad s^-1`
Moment of inertia of the solid cylinder about its axis is.
`I = (MR^2)/(2) = ((20 kg)(20 xx 10^-2 m)^2)/(2) = 0.4 kg m^2`
Angular momentum of the cylinder about axis is.
`L = I omega = (0.4 kg m^2)(100 rad s^-1) = 40 J s`.


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