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An uncharged capacitor is connected to a battery. Show that half the energy supplied by the battery is lost as heat while charging the capacitor. |
Answer» Let capacitance of a capacitor = C emf of the battery = V `:.` Charge given to the capacitor, q = CV Energy supplied by battery = work done by battery = qV Energy stored in the capacitor `= (1)/(2) CV^(2) = (1)/(2) qV` So, half energy is lost as beat while charging the capacitor. |
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