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An unknown gas diffuses 5 times less than that of H2.what is the molecular mass of the unknown gas? |
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Answer» answer is 50 Explanation: the rate of DIFFUSION of H2 gas =r2 the rate of diffusion of unknown gas ,r1=5r2 molecular mass of unknown gass =M1 molcular mass of H2 gas=2 rate of diffusion =√molecular mass of unknown gas /Molecular mass of H2 gas r1/r2=√M1/2 5r2/r2=√M1/2 5/1=√M1/2 squaring on both sides 25/1=M1/2 M1=50 i hope it is helpful!! |
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