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An unknown particle having double charge as proton itself moves with wavelenght lambda, if it is accelerated from rest through a potential difference of(V)/(8)voltus. While proton itself moves with same wavelenght lambda when acceleratedfrom rest thought a potentialdifference 'V' volts. Theparticls is |
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Answer» `He^(+)` `(lambda)=(h)/sqrt(2xxm'xx2exx(V)/(8))` `mxx2exx(V)/(8)=mxxexxv` `m'=4m` |
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