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An urn contains 25 balls of which I0 balls bear a mark 'X' and remaining 15 bear a mark 'Y'. A ball is drawn at random from the urn, its mark is noted down and it is replaced. If 6 balls are drawn in this way, find the probability that i. all will bear 'X'mark ii. not more than 2 will bear 'Y' mark iii. atlest one ball will bear 'Y' mark iv. the number of balls with 'X' marks and 'Y' mark will be equal

Answer»


Answer :i. `((2)/(5))^(6)`, ii. `7((2)/(5))^(4)` , III. `1-((2)/(5))^(6)` and IV. `(864)/(3125)`


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